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Mesaj |
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Postati aici intrebari legate de problemele din aceasta varianta.
--- Pitagora,
Pro-Didactician
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ex 2.
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f(x+1)-f(x)=f(x)-f(x-1) si f(1)=f(0)+2
sa da valori nr natural 1,2,..2007
f(2)-f(1)=f(1)-f(0)
f(3)-f(2)=f(2)-f(1)
f(4)-f(3)=f(3)-f(2)
f(5)-f(4)=f(4)-f(3
..............................
f(2006)-f(2005)=f(2005)-f(2004)
f(2007)-f(2006)=f(2006)-f(2005)
f(2008)-f(2007)=f(2007)-f(2006)
se aduna si se obtine
f(2008)-f(1)=f(2007)-f(0)
f(2008)-f(2007)=f(1)-f(0)=f(0)+2-f(0)=2
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