(9/4)^3x+1 * sqrt(8/27)^6x = 3/2 va rog sa ma ajutati cu rezolvarea ei.

Pacat ca nu stiu sa folosesc LATEX..Sa vedem daca intelegi:

(9/4)^3x+1 = (9/4)* (9/4)^3x
sqrt(8/27)^6x=(sqrt(8/27)^2)^3x= (8/27)^3x

Inmultind si notand expresia initiala cu E, avem
E=(9/4)* [(9/4)^3x] * [(8/27)^3x] = 3/2 <=> [(9/4)*(8/27)]^3x = (3/2)*(4/9), deci (2/3)^3x=2/3 => 3x=1 => x=1/3.

Cred ca asa...

multumesc! :D

Cu placere